Fixed dependent product rules, hopefully final now.

1 files changed, 27 insertions, 72 deletions

diff --git a/HoTT_Theorems.thy b/HoTT_Theorems.thy
index d83a08c..10a0d2c 100644
--- a/HoTT_Theorems.thy
+++ b/HoTT_Theorems.thy
@@ -6,10 +6,11 @@ text "A bunch of theorems and other statements for sanity-checking, as well as t
 
 Things that *should* be automated:
   \<bullet> Checking that \<open>A\<close> is a well-formed type, when writing things like \<open>x : A\<close> and \<open>A : U\<close>.
-  \<bullet> Checking that the argument to a (dependent/non-dependent) function matches the type? Also the arguments to a pair?"
+  \<bullet> Checking that the argument to a (dependent/non-dependent) function matches the type? Also the arguments to a pair?
+"
 
 \<comment> \<open>Turn on trace for unification and the simplifier, for debugging.\<close>
-declare[[unify_trace_simp, unify_trace_types, simp_trace, simp_trace_depth_limit=2]]
+declare[[unify_trace_simp, unify_trace_types, simp_trace, simp_trace_depth_limit=1]]
 
 section \<open>Functions\<close>
 
@@ -17,97 +18,51 @@ subsection \<open>Typing functions\<close>
 
 text "Declaring \<open>Prod_intro\<close> with the \<open>intro\<close> attribute (in HoTT.thy) enables \<open>standard\<close> to prove the following."
 
-lemma id_function: "A : U \<Longrightarrow> \<^bold>\<lambda>x:A. x : A\<rightarrow>A" ..
+lemma "\<^bold>\<lambda>x:A. x : A\<rightarrow>A" ..
 
-text "Here is the same result, stated and proved differently.
-The standard method invoked after the keyword \<open>proof\<close> is applied to the goal \<open>\<^bold>\<lambda>x. x: A\<rightarrow>A\<close>, and so we need to show the prover how to continue, as opposed to the previous lemma."
-
-lemma
-  assumes "A : U"
-  shows "\<^bold>\<lambda>x:A. x : A\<rightarrow>A"
-proof
-  show "A : U" using assms .
-  show "\<lambda>x. A : A \<rightarrow> U" using assms ..
-qed
-
-text "Note that there is no provision for declaring the type of bound variables outside of the scope of a lambda expression.
-More generally, we cannot write an assumption stating 'Let \<open>x\<close> be a variable of type \<open>A\<close>'."
-
-proposition "\<lbrakk>A : U; A \<equiv> B\<rbrakk> \<Longrightarrow> \<^bold>\<lambda>x:A. x : B\<rightarrow>A"
+proposition "A \<equiv> B \<Longrightarrow> \<^bold>\<lambda>x:A. x : B\<rightarrow>A"
 proof -
-  assume
-    1: "A : U" and
-    2: "A \<equiv> B"
-  from id_function[OF 1] have 3: "\<^bold>\<lambda>x:A. x : A\<rightarrow>A" .
-  from 2 have "A\<rightarrow>A \<equiv> B\<rightarrow>A" by simp
-  with 3 show "\<^bold>\<lambda>x:A. x : B\<rightarrow>A" ..
-qed
-
-text "It is instructive to try to prove \<open>\<lbrakk>A : U; B : U\<rbrakk> \<Longrightarrow> \<^bold>\<lambda>x. \<^bold>\<lambda>y. x : A\<rightarrow>B\<rightarrow>A\<close>.
-First we prove an intermediate step."
-
-lemma constant_function: "\<lbrakk>A : U; B : U; x : A\<rbrakk> \<Longrightarrow> \<^bold>\<lambda>y:B. x : B\<rightarrow>A" ..
-
-text "And now the actual result:"
-
-proposition
-  assumes 1: "A : U" and 2: "B : U"
-  shows "\<^bold>\<lambda>x:A. \<^bold>\<lambda>y:B. x : A\<rightarrow>B\<rightarrow>A"
-proof
-  show "A : U" using assms(1) .
-  show "\<And>x. x : A \<Longrightarrow> \<^bold>\<lambda>y:B. x : B \<rightarrow> A" using assms by (rule constant_function)
-
-  from assms have "B \<rightarrow> A : U" by (rule Prod_formation)
-  then show "\<lambda>x. B \<rightarrow> A: A \<rightarrow> U" using assms(1) by (rule constant_type_family)
+  assume assm: "A \<equiv> B"
+  have id: "\<^bold>\<lambda>x:A. x : A\<rightarrow>A" ..
+  from assm have "A\<rightarrow>A \<equiv> B\<rightarrow>A" by simp
+  with id show "\<^bold>\<lambda>x:A. x : B\<rightarrow>A" ..
 qed
 
-text "Maybe a nicer way to write it:"
-
-proposition alternating_function: "\<lbrakk>A : U; B: U\<rbrakk> \<Longrightarrow> \<^bold>\<lambda>x:A. \<^bold>\<lambda>y:B. x : A\<rightarrow>B\<rightarrow>A"
+proposition "\<^bold>\<lambda>x:A. \<^bold>\<lambda>y:B. x : A\<rightarrow>B\<rightarrow>A"
 proof
-  fix x
-  show "\<lbrakk>A : U;  B : U; x : A\<rbrakk> \<Longrightarrow> \<^bold>\<lambda>y:B. x : B \<rightarrow> A" by (rule constant_function)
-  show "\<lbrakk>A : U; B : U\<rbrakk> \<Longrightarrow> B\<rightarrow>A : U" by (rule Prod_formation)
+  fix a
+  assume "a : A"
+  then show "\<^bold>\<lambda>y:B. a : B \<rightarrow> A" .. 
 qed
 
 subsection \<open>Function application\<close>
 
-lemma "\<lbrakk>A : U; a : A\<rbrakk> \<Longrightarrow> (\<^bold>\<lambda>x:A. x)`a \<equiv> a" by simp
+proposition "\<lbrakk>A : U; a : A\<rbrakk> \<Longrightarrow> (\<^bold>\<lambda>x:A. x)`a \<equiv> a" by simp
+
+text "Two arguments:"
 
 lemma
-  assumes
-    "A:U" and
-    "B:U" and
-    "a:A" and
-    "b:B"
+  assumes "a:A" and "b:B"
   shows "(\<^bold>\<lambda>x:A. \<^bold>\<lambda>y:B. x)`a`b \<equiv> a"
 proof -
   have "(\<^bold>\<lambda>x:A. \<^bold>\<lambda>y:B. x)`a \<equiv> \<^bold>\<lambda>y:B. a" 
-    proof (rule Prod_comp[of A "\<lambda>_. B\<rightarrow>A"])
-      have "B \<rightarrow> A : U" using constant_type_family[OF assms(1) assms(2)] assms(2) by (rule Prod_formation)
-      then show "\<lambda>x. B \<rightarrow> A: A \<rightarrow> U" using assms(1) by (rule constant_type_family[of "B\<rightarrow>A"])
-      
-      show "\<And>x. x : A \<Longrightarrow> \<^bold>\<lambda>y:B. x : B \<rightarrow> A" using assms(2) assms(1) ..
-      show "A:U" using assms(1) .
-      show "a:A" using assms(3) .
-    qed  (* Why do I need to do the above for the last two goals? Can't Isabelle do it automatically? *)
-
+    proof (rule Prod_comp[of A _ "\<lambda>_. B\<rightarrow>A"])
+      fix x
+      assume "x:A"
+      then show "\<^bold>\<lambda>y:B. x : B \<rightarrow> A" ..
+    qed (rule assms)
   then have "(\<^bold>\<lambda>x:A. \<^bold>\<lambda>y:B. x)`a`b \<equiv> (\<^bold>\<lambda>y:B. a)`b" by simp
-
-  also have "(\<^bold>\<lambda>y:B. a)`b \<equiv> a"
-    proof (rule Prod_comp[of B "\<lambda>_. A"])
-      show "\<lambda>y. A: B \<rightarrow> U" using assms(1) assms(2) by (rule constant_type_family)
-      show "\<And>y. y : B \<Longrightarrow> a : A" using assms(3) .
-      show "B:U" using assms(2) .
-      show "b:B" using assms(4) .
-    qed
-
+  also have "(\<^bold>\<lambda>y:B. a)`b \<equiv> a" using assms by (simp add: Prod_comp[of B _ "\<lambda>_. A"])
   finally show "(\<^bold>\<lambda>x:A. \<^bold>\<lambda>y:B. x)`a`b \<equiv> a" .
 qed
 
+text "Note that the propositions and proofs above often say nothing about the well-formedness of the types, or the well-typedness of the lambdas involved; one has to be very explicit and prove such things separately!
+This is the result of the choices made regarding the premises of the type rules."
+
 text "Polymorphic identity function."
 
 consts Ui::Term
+
 definition Id where "Id \<equiv> \<^bold>\<lambda>A:Ui. \<^bold>\<lambda>x:A. x"
 (* Have to think about universes... *)