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theory Equivalence
imports Identity
begin
section \<open>Homotopy\<close>
definition "homotopy A B f g \<equiv> \<Prod>x: A. f `x =\<^bsub>B x\<^esub> g `x"
definition homotopy_i (infix "~" 100)
where [implicit]: "f ~ g \<equiv> homotopy ? ? f g"
translations "f ~ g" \<leftharpoondown> "CONST homotopy A B f g"
Lemma homotopy_type [typechk]:
assumes
"A: U i"
"\<And>x. x: A \<Longrightarrow> B x: U i"
"f: \<Prod>x: A. B x" "g: \<Prod>x: A. B x"
shows "f ~ g: U i"
unfolding homotopy_def by typechk
Lemma (derive) homotopy_refl [refl]:
assumes
"A: U i"
"f: \<Prod>x: A. B x"
shows "f ~ f"
unfolding homotopy_def by intros
Lemma (derive) hsym:
assumes
"f: \<Prod>x: A. B x"
"g: \<Prod>x: A. B x"
"A: U i"
"\<And>x. x: A \<Longrightarrow> B x: U i"
shows "H: f ~ g \<Longrightarrow> g ~ f"
unfolding homotopy_def
apply intros
apply (rule pathinv)
\<guillemotright> by (elim H)
\<guillemotright> by typechk
done
Lemma (derive) htrans:
assumes
"f: \<Prod>x: A. B x"
"g: \<Prod>x: A. B x"
"h: \<Prod>x: A. B x"
"A: U i"
"\<And>x. x: A \<Longrightarrow> B x: U i"
shows "\<lbrakk>H1: f ~ g; H2: g ~ h\<rbrakk> \<Longrightarrow> f ~ h"
unfolding homotopy_def
apply intro
\<guillemotright> vars x
apply (rule pathcomp[where ?y="g x"])
\<^item> by (elim H1)
\<^item> by (elim H2)
done
\<guillemotright> by typechk
done
text \<open>For calculations:\<close>
congruence "f ~ g" rhs g
lemmas
homotopy_sym [sym] = hsym[rotated 4] and
homotopy_trans [trans] = htrans[rotated 5]
Lemma (derive) commute_homotopy:
assumes
"A: U i" "B: U i"
"x: A" "y: A"
"p: x =\<^bsub>A\<^esub> y"
"f: A \<rightarrow> B" "g: A \<rightarrow> B"
"H: homotopy A (\<lambda>_. B) f g"
shows "(H x) \<bullet> g[p] = f[p] \<bullet> (H y)"
\<comment> \<open>Need this assumption unfolded for typechecking:\<close>
supply assms(8)[unfolded homotopy_def]
apply (eq p)
focus vars x
apply reduce
\<comment> \<open>Here it would really be nice to have automation for transport and
propositional equality.\<close>
apply (rule use_transport[where ?y="H x \<bullet> refl (g x)"])
\<guillemotright> by (rule pathcomp_refl)
\<guillemotright> by (rule pathinv) (rule refl_pathcomp)
\<guillemotright> by typechk
done
done
Corollary (derive) commute_homotopy':
assumes
"A: U i"
"x: A"
"f: A \<rightarrow> A"
"H: homotopy A (\<lambda>_. A) f (id A)"
shows "H (f x) = f [H x]"
oops
Lemma homotopy_id_left [typechk]:
assumes "A: U i" "B: U i" "f: A \<rightarrow> B"
shows "homotopy_refl A f: (id B) \<circ> f ~ f"
unfolding homotopy_refl_def homotopy_def by reduce
Lemma homotopy_id_right [typechk]:
assumes "A: U i" "B: U i" "f: A \<rightarrow> B"
shows "homotopy_refl A f: f \<circ> (id A) ~ f"
unfolding homotopy_refl_def homotopy_def by reduce
Lemma homotopy_funcomp_left:
assumes
"H: homotopy B C g g'"
"f: A \<rightarrow> B"
"g: \<Prod>x: B. C x"
"g': \<Prod>x: B. C x"
"A: U i" "B: U i"
"\<And>x. x: B \<Longrightarrow> C x: U i"
shows "homotopy A {} (g \<circ>\<^bsub>A\<^esub> f) (g' \<circ>\<^bsub>A\<^esub> f)"
unfolding homotopy_def
apply (intro; reduce)
apply (insert \<open>H: _\<close>[unfolded homotopy_def])
apply (elim H)
done
Lemma homotopy_funcomp_right:
assumes
"H: homotopy A (\<lambda>_. B) f f'"
"f: A \<rightarrow> B"
"f': A \<rightarrow> B"
"g: B \<rightarrow> C"
"A: U i" "B: U i" "C: U i"
shows "homotopy A {} (g \<circ>\<^bsub>A\<^esub> f) (g \<circ>\<^bsub>A\<^esub> f')"
unfolding homotopy_def
apply (intro; reduce)
apply (insert \<open>H: _\<close>[unfolded homotopy_def])
apply (dest PiE, assumption)
apply (rule ap, assumption)
done
section \<open>Quasi-inverse and bi-invertibility\<close>
subsection \<open>Quasi-inverses\<close>
definition "qinv A B f \<equiv> \<Sum>g: B \<rightarrow> A.
homotopy A (\<lambda>_. A) (g \<circ>\<^bsub>A\<^esub> f) (id A) \<times> homotopy B (\<lambda>_. B) (f \<circ>\<^bsub>B\<^esub> g) (id B)"
lemma qinv_type [typechk]:
assumes "A: U i" "B: U i" "f: A \<rightarrow> B"
shows "qinv A B f: U i"
unfolding qinv_def by typechk
definition qinv_i ("qinv")
where [implicit]: "qinv f \<equiv> Equivalence.qinv ? ? f"
translations "qinv f" \<leftharpoondown> "CONST Equivalence.qinv A B f"
Lemma (derive) id_qinv:
assumes "A: U i"
shows "qinv (id A)"
unfolding qinv_def
apply intro defer
apply intro defer
apply (rule homotopy_id_right)
apply (rule homotopy_id_left)
done
Lemma (derive) quasiinv_qinv:
assumes "A: U i" "B: U i" "f: A \<rightarrow> B"
shows "prf: qinv f \<Longrightarrow> qinv (fst prf)"
unfolding qinv_def
apply intro
\<guillemotright> by (rule \<open>f:_\<close>)
\<guillemotright> apply (elim "prf")
focus vars g HH
apply intro
\<^item> by reduce (snd HH)
\<^item> by reduce (fst HH)
done
done
done
Lemma (derive) funcomp_qinv:
assumes
"A: U i" "B: U i" "C: U i"
"f: A \<rightarrow> B" "g: B \<rightarrow> C"
shows "qinv f \<rightarrow> qinv g \<rightarrow> qinv (g \<circ> f)"
apply (intros, unfold qinv_def, elims)
focus
prems prms
vars _ _ finv _ ginv _ HfA HfB HgB HgC
apply intro
apply (rule funcompI[where ?f=ginv and ?g=finv])
text \<open>Now a whole bunch of rewrites and we're done.\<close>
oops
subsection \<open>Bi-invertible maps\<close>
definition "biinv A B f \<equiv>
(\<Sum>g: B \<rightarrow> A. homotopy A (\<lambda>_. A) (g \<circ>\<^bsub>A\<^esub> f) (id A))
\<times> (\<Sum>g: B \<rightarrow> A. homotopy B (\<lambda>_. B) (f \<circ>\<^bsub>B\<^esub> g) (id B))"
lemma biinv_type [typechk]:
assumes "A: U i" "B: U i" "f: A \<rightarrow> B"
shows "biinv A B f: U i"
unfolding biinv_def by typechk
definition biinv_i ("biinv")
where [implicit]: "biinv f \<equiv> Equivalence.biinv ? ? f"
translations "biinv f" \<leftharpoondown> "CONST Equivalence.biinv A B f"
Lemma (derive) qinv_imp_biinv:
assumes
"A: U i" "B: U i"
"f: A \<rightarrow> B"
shows "?prf: qinv f \<rightarrow> biinv f"
apply intros
unfolding qinv_def biinv_def
by (rule Sig_dist_exp)
text \<open>
Show that bi-invertible maps are quasi-inverses, as a demonstration of how to
work in this system.
\<close>
Lemma (derive) biinv_imp_qinv:
assumes "A: U i" "B: U i" "f: A \<rightarrow> B"
shows "biinv f \<rightarrow> qinv f"
text \<open>Split the hypothesis \<^term>\<open>biinv f\<close> into its components:\<close>
apply intro
unfolding biinv_def
apply elims
text \<open>Name the components:\<close>
focus prems vars _ _ _ g H1 h H2
thm \<open>g:_\<close> \<open>h:_\<close> \<open>H1:_\<close> \<open>H2:_\<close>
text \<open>
\<^term>\<open>g\<close> is a quasi-inverse to \<^term>\<open>f\<close>, so the proof will be a triple
\<^term>\<open><g, <?H1, ?H2>>\<close>.
\<close>
unfolding qinv_def
apply intro
\<guillemotright> by (rule \<open>g: _\<close>)
\<guillemotright> apply intro
text \<open>The first part \<^prop>\<open>?H1: g \<circ> f ~ id A\<close> is given by \<^term>\<open>H1\<close>.\<close>
apply (rule \<open>H1: _\<close>)
text \<open>
It remains to prove \<^prop>\<open>?H2: f \<circ> g ~ id B\<close>. First show that \<open>g ~ h\<close>,
then the result follows from @{thm \<open>H2: f \<circ> h ~ id B\<close>}. Here a proof
block is used to calculate "forward".
\<close>
proof -
have "g ~ g \<circ> (id B)" by reduce refl
also have ".. ~ g \<circ> f \<circ> h"
by (rule homotopy_funcomp_right) (rule \<open>H2:_\<close>[symmetric])
also have ".. ~ (id A) \<circ> h"
by (subst funcomp_assoc[symmetric])
(rule homotopy_funcomp_left, rule \<open>H1:_\<close>)
also have ".. ~ h" by reduce refl
finally have "g ~ h" by this
then have "f \<circ> g ~ f \<circ> h" by (rule homotopy_funcomp_right)
with \<open>H2:_\<close>
show "f \<circ> g ~ id B"
by (rule homotopy_trans) (assumption+, typechk)
qed
done
done
Lemma (derive) id_biinv:
"A: U i \<Longrightarrow> biinv (id A)"
by (rule qinv_imp_biinv) (rule id_qinv)
Lemma (derive) funcomp_biinv:
assumes
"A: U i" "B: U i" "C: U i"
"f: A \<rightarrow> B" "g: B \<rightarrow> C"
shows "biinv f \<rightarrow> biinv g \<rightarrow> biinv (g \<circ> f)"
apply intros
focus vars biinv\<^sub>f biinv\<^sub>g
text \<open>Follows from \<open>funcomp_qinv\<close>.\<close>
oops
section \<open>Equivalence\<close>
text \<open>
Following the HoTT book, we first define equivalence in terms of
bi-invertibility.
\<close>
definition equivalence (infix "\<simeq>" 110)
where "A \<simeq> B \<equiv> \<Sum>f: A \<rightarrow> B. Equivalence.biinv A B f"
lemma equivalence_type [typechk]:
assumes "A: U i" "B: U i"
shows "A \<simeq> B: U i"
unfolding equivalence_def by typechk
Lemma (derive) equivalence_refl:
assumes "A: U i"
shows "A \<simeq> A"
unfolding equivalence_def
apply intro defer
apply (rule qinv_imp_biinv) defer
apply (rule id_qinv)
done
text \<open>
The following could perhaps be easier with transport (but then I think we need
univalence?)...
\<close>
Lemma (derive) equivalence_symmetric:
assumes "A: U i" "B: U i"
shows "A \<simeq> B \<rightarrow> B \<simeq> A"
apply intros
unfolding equivalence_def
apply elim
\<guillemotright> vars _ f "prf"
apply (dest (4) biinv_imp_qinv)
apply intro
\<^item> unfolding qinv_def by (rule fst[of "(biinv_imp_qinv A B f) prf"])
\<^item> by (rule qinv_imp_biinv) (rule quasiinv_qinv)
done
done
Lemma (derive) equivalence_transitive:
assumes "A: U i" "B: U i" "C: U i"
shows "A \<simeq> B \<rightarrow> B \<simeq> C \<rightarrow> A \<simeq> C"
apply intros
unfolding equivalence_def
text \<open>Use \<open>funcomp_biinv\<close>.\<close>
oops
text \<open>
Equal types are equivalent. We give two proofs: the first by induction, and
the second by following the HoTT book and showing that transport is an
equivalence.
\<close>
Lemma
assumes "A: U i" "B: U i" "p: A =\<^bsub>U i\<^esub> B"
shows "A \<simeq> B"
by (eq p) (rule equivalence_refl)
text \<open>
The following proof is wordy because (1) the typechecker doesn't rewrite, and
(2) we don't yet have universe automation.
\<close>
Lemma (derive) id_imp_equiv:
assumes
"A: U i" "B: U i" "p: A =\<^bsub>U i\<^esub> B"
shows "<trans (id (U i)) p, ?isequiv>: A \<simeq> B"
unfolding equivalence_def
apply intros defer
\<comment> \<open>Switch off auto-typechecking, which messes with universe levels\<close>
supply [[auto_typechk=false]]
\<guillemotright> apply (eq p, typechk)
\<^item> prems vars A B
apply (rewrite at A in "A \<rightarrow> B" id_comp[symmetric])
apply (rewrite at B in "_ \<rightarrow> B" id_comp[symmetric])
apply (rule transport, rule U_in_U)
apply (rule lift_universe_codomain, rule U_in_U)
apply (typechk, rule U_in_U)
done
\<^item> prems vars A
apply (subst transport_comp)
\<^enum> by (rule U_in_U)
\<^enum> by reduce (rule lift_universe)
\<^enum> by reduce (rule id_biinv)
done
done
\<guillemotright> \<comment> \<open>Similar proof as in the first subgoal above\<close>
apply (rewrite at A in "A \<rightarrow> B" id_comp[symmetric])
apply (rewrite at B in "_ \<rightarrow> B" id_comp[symmetric])
apply (rule transport, rule U_in_U)
apply (rule lift_universe_codomain, rule U_in_U)
apply (typechk, rule U_in_U)
done
done
(*Uncomment this to see all implicits from here on.
no_translations
"f x" \<leftharpoondown> "f `x"
"x = y" \<leftharpoondown> "x =\<^bsub>A\<^esub> y"
"g \<circ> f" \<leftharpoondown> "g \<circ>\<^bsub>A\<^esub> f"
"p\<inverse>" \<leftharpoondown> "CONST pathinv A x y p"
"p \<bullet> q" \<leftharpoondown> "CONST pathcomp A x y z p q"
"fst" \<leftharpoondown> "CONST Spartan.fst A B"
"snd" \<leftharpoondown> "CONST Spartan.snd A B"
"f[p]" \<leftharpoondown> "CONST ap A B x y f p"
"trans P p" \<leftharpoondown> "CONST transport A P x y p"
"trans_const B p" \<leftharpoondown> "CONST transport_const A B x y p"
"lift P p u" \<leftharpoondown> "CONST pathlift A P x y p u"
"apd f p" \<leftharpoondown> "CONST Identity.apd A P f x y p"
"f ~ g" \<leftharpoondown> "CONST homotopy A B f g"
"qinv f" \<leftharpoondown> "CONST Equivalence.qinv A B f"
"biinv f" \<leftharpoondown> "CONST Equivalence.biinv A B f"
*)
end
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