Prod.thy now has the correct definitional equality structure rule. Definition of function composition and properties.

1 files changed, 77 insertions, 23 deletions

diff --git a/ProdProps.thy b/ProdProps.thy
index 7c2c658..e48b3e6 100644
--- a/ProdProps.thy
+++ b/ProdProps.thy
@@ -15,40 +15,94 @@ begin
 section \<open>Composition\<close>
 
 text "
-  The following rule is admissible, but we cannot derive it only using the rules for the \<Pi>-type.
+  The proof of associativity is surprisingly intricate; it involves telling Isabelle to use the correct rule for \<Pi>-type judgmental equality, and the correct substitutions in the subgoals thereafter, among other things.
 "
 
-lemma compose_comp': "\<lbrakk>
-    A: U(i);
-    \<And>x. x: A \<Longrightarrow> b(x): B;
-    \<And>x. x: B \<Longrightarrow> c(x): C(x)
-  \<rbrakk> \<Longrightarrow> (\<^bold>\<lambda>x. c(x)) \<circ> (\<^bold>\<lambda>x. b(x)) \<equiv> \<^bold>\<lambda>x. c(b(x))"
+lemma compose_assoc:
+  assumes
+    "A \<rightarrow> B: U(i)" "B \<rightarrow> C: U(i)" and
+    "\<Prod>x:C. D(x): U(i)" and
+    "f: A \<rightarrow> B" "g: B \<rightarrow> C" "h: \<Prod>x:C. D(x)"
+  shows "(h \<circ> g) \<circ> f \<equiv> h \<circ> (g \<circ> f)"
+
+proof (subst (0 1 2 3) compose_def)
+  text "Compute the different bracketings and show they are equivalent:"
+
+  show "\<^bold>\<lambda>x. (\<^bold>\<lambda>y. h`(g`y))`(f`x) \<equiv> \<^bold>\<lambda>x. h`((\<^bold>\<lambda>y. g`(f`y))`x)"
+  proof (subst Prod_eq)
+  show "\<^bold>\<lambda>x. h`((\<^bold>\<lambda>y. g`(f`y))`x) \<equiv> \<^bold>\<lambda>x. h`((\<^bold>\<lambda>y. g`(f`y))`x)" by simp
+    show "\<And>x. x: A \<Longrightarrow> (\<^bold>\<lambda>y. h`(g`y))`(f`x) \<equiv> h`((\<^bold>\<lambda>y. g`(f`y))`x)"
+    proof compute
+      show "\<And>x. x: A \<Longrightarrow> h`(g`(f`x)) \<equiv> h`((\<^bold>\<lambda>y. g`(f`y))`x)"
+      proof compute
+        show "\<And>x. x: A \<Longrightarrow> g`(f`x): C" by (simple lems: assms)
+      qed
+      show "\<And>x. x: B \<Longrightarrow> h`(g`x): D(g`x)" by (simple lems: assms)
+    qed (simple lems: assms)
+  qed (wellformed lems: assms)
+
+  text "
+    Finish off any remaining subgoals that Isabelle can't prove automatically.
+    These typically require the application of specific substitutions or computation rules.
+  "
+  show "g \<circ> f: A \<rightarrow> C" by (subst compose_def) (derive lems: assms)
+
+  show "h \<circ> g: \<Prod>x:B. D(g`x)"
+  proof (subst compose_def)
+    show "\<^bold>\<lambda>x. h`(g`x): \<Prod>x:B. D(g`x)"
+    proof
+      show "\<And>x. x: B \<Longrightarrow> h`(g`x): D(g`x)"
+      proof
+        show "\<And>x. x: B \<Longrightarrow> g`x: C" by (simple lems: assms)
+      qed (simple lems: assms)
+    qed (wellformed lems: assms)
+  qed fact+
+  
+  show "\<Prod>x:B. D (g`x): U(i)"
+  proof
+    show "\<And>x. x: B \<Longrightarrow> D(g`x): U(i)"
+    proof -
+      have *: "D: C \<longrightarrow> U(i)" by (wellformed lems: assms)
+      
+      fix x assume asm: "x: B"
+      have "g`x: C" by (simple lems: assms asm)
+      then show "D(g`x): U(i)" by (rule *)
+    qed
+  qed (wellformed lems: assms)
+
+  have "A: U(i)" by (wellformed lems: assms)
+  moreover have "C: U(i)" by (wellformed lems: assms)
+  ultimately show "A \<rightarrow> C: U(i)" ..
+qed (simple lems: assms)
+
+
+text "The following rule is correct, but we cannot prove it using just the rules of the theory."
+
+lemma compose_comp':
+  assumes "A: U(i)" and "\<And>x. x: A \<Longrightarrow> b(x): B" and "\<And>x. x: B \<Longrightarrow> c(x): C(x)"
+  shows "(\<^bold>\<lambda>x. c(x)) \<circ> (\<^bold>\<lambda>x. b(x)) \<equiv> \<^bold>\<lambda>x. c(b(x))"
 oops
 
 text "However we can derive a variant with more explicit premises:"
 
-lemma compose_comp2:
+lemma compose_comp:
   assumes
-    "A: U(i)" "B: U(i)" and
-    "C: B \<longrightarrow> U(i)" and
+    "A: U(i)" "B: U(i)" "C: B \<longrightarrow> U(i)" and
     "\<And>x. x: A \<Longrightarrow> b(x): B" and
     "\<And>x. x: B \<Longrightarrow> c(x): C(x)"
   shows "(\<^bold>\<lambda>x. c(x)) \<circ> (\<^bold>\<lambda>x. b(x)) \<equiv> \<^bold>\<lambda>x. c(b(x))"
-proof (subst (0) comp)
-  show "\<^bold>\<lambda>x. (\<^bold>\<lambda>u. c(u))`((\<^bold>\<lambda>v. b(v))`x) \<equiv> \<^bold>\<lambda>x. c(b(x))"
-  proof (subst (0) comp)
-    show "\<^bold>\<lambda>x. c((\<^bold>\<lambda>v. b(v))`x) \<equiv> \<^bold>\<lambda>x. c(b(x))"
-    proof -
-      have *: "\<And>x. x: A \<Longrightarrow> (\<^bold>\<lambda>v. b(v))`x \<equiv> b(x)" by simple (rule assms)
-      show "\<^bold>\<lambda>x. c((\<^bold>\<lambda>v. b(v))`x) \<equiv> \<^bold>\<lambda>x. c(b(x))"
-      proof (subst *)
-
+proof (subst compose_def)
+  show "\<^bold>\<lambda>x. (\<^bold>\<lambda>x. c(x))`((\<^bold>\<lambda>x. b(x))`x) \<equiv> \<^bold>\<lambda>x. c(b(x))"
+  proof
+    show "\<And>a. a: A \<Longrightarrow> (\<^bold>\<lambda>x. c(x))`((\<^bold>\<lambda>x. b(x))`a) \<equiv> c(b(a))"
+    proof compute
+      show "\<And>a. a: A \<Longrightarrow> c((\<^bold>\<lambda>x. b(x))`a) \<equiv> c(b(a))" by compute (simple lems: assms)
+    qed (simple lems: assms)
+  qed fact
+qed (simple lems: assms)
 
-text "We can show associativity of composition in general."
 
-lemma compose_assoc:
-  "(f \<circ> g) \<circ> h \<equiv> f \<circ> (g \<circ> h)"
-proof 
+lemmas compose_comps [comp] = compose_def compose_comp
 
 
-end
\ No newline at end of file
+end