(* Title: HoTT/EqualProps.thy Author: Josh Chen Date: Jun 2018 Properties of equality. *) theory EqualProps imports HoTT_Methods Equal Prod begin section \Symmetry / Path inverse\ definition inv :: "[Term, Term, Term] \ Term" ("(1inv[_,/ _,/ _])") where "inv[A,x,y] \ \<^bold>\p: (x =\<^sub>A y). indEqual[A] (\x y _. y =\<^sub>A x) (\x. refl(x)) x y p" lemma inv_type: assumes "p : x =\<^sub>A y" shows "inv[A,x,y]`p : y =\<^sub>A x" proof show "inv[A,x,y] : (x =\<^sub>A y) \ (y =\<^sub>A x)" proof (unfold inv_def, standard) fix p assume asm: "p : x =\<^sub>A y" show "indEqual[A] (\x y _. y =[A] x) refl x y p : y =\<^sub>A x" proof standard+ show "x : A" by (wellformed jdgmt: asm) show "y : A" by (wellformed jdgmt: asm) qed (assumption | rule | rule asm)+ qed (wellformed jdgmt: assms) qed (rule assms) lemma inv_comp: assumes "a : A" shows "inv[A,a,a]`refl(a) \ refl(a)" proof - have "inv[A,a,a]`refl(a) \ indEqual[A] (\x y _. y =\<^sub>A x) (\x. refl(x)) a a refl(a)" proof (unfold inv_def, standard) show "refl(a) : a =\<^sub>A a" using assms .. fix p assume asm: "p : a =\<^sub>A a" show "indEqual[A] (\x y _. y =\<^sub>A x) refl a a p : a =\<^sub>A a" proof standard+ show "a : A" by (wellformed jdgmt: asm) then show "a : A" . \ \The elimination rule requires that both arguments to \indEqual\ be shown to have the correct type.\ qed (assumption | rule | rule asm)+ qed also have "indEqual[A] (\x y _. y =\<^sub>A x) (\x. refl(x)) a a refl(a) \ refl(a)" by (standard | assumption | rule assms)+ finally show "inv[A,a,a]`refl(a) \ refl(a)" . qed section \Transitivity / Path composition\ \ \"Raw" composition function\ definition compose' :: "Term \ Term" ("(1compose''[_])") where "compose'[A] \ indEqual[A] (\x y _. \z:A. \q: y =\<^sub>A z. x =\<^sub>A z) (indEqual[A](\x z _. x =\<^sub>A z) (\<^bold>\x:A. refl(x)))" \ \"Natural" composition function\ abbreviation compose :: "[Term, Term, Term, Term] \ Term" ("(1compose[_,/ _,/ _,/ _])") where "compose[A,x,y,z] \ \<^bold>\p:x =\<^sub>A y. \<^bold>\q:y =\<^sub>A z. compose'[A]`x`y`p`z`q" (**** GOOD CANDIDATE FOR AUTOMATION ****) lemma compose_comp: assumes "a : A" shows "compose[A,a,a,a]`refl(a)`refl(a) \ refl(a)" using assms Equal_intro[OF assms] unfolding compose'_def by simp text "The above proof is a good candidate for proof automation; in particular we would like the system to be able to automatically find the conditions of the \using\ clause in the proof. This would likely involve something like: 1. Recognizing that there is a function application that can be simplified. 2. Noting that the obstruction to applying \Prod_comp\ is the requirement that \refl(a) : a =\<^sub>A a\. 3. Obtaining such a condition, using the known fact \a : A\ and the introduction rule \Equal_intro\." lemmas Equal_simps [simp] = inv_comp compose_comp subsubsection \Pretty printing\ abbreviation inv_pretty :: "[Term, Term, Term, Term] \ Term" ("(1_\<^sup>-\<^sup>1[_, _, _])" 500) where "p\<^sup>-\<^sup>1[A,x,y] \ inv[A,x,y]`p" abbreviation compose_pretty :: "[Term, Term, Term, Term, Term, Term] \ Term" ("(1_ \[_, _, _, _]/ _)") where "p \[A,x,y,z] q \ compose[A,x,y,z]`p`q"